One Equals Zero
Proving 1=0, 2=1, and so on…
Here is a pretty tricky proof that I’ve come across several times. It basically proves that a+b=a, which would mean that 1+0=0, 1=0, 2=1, and so on.
I know very well how to prove this wrong, but do you? 
a = b
ab = b²
ab - a² = b² - a²
a(b - a) = (b + a)(b - a)
a = b + a
If a and b are 1, then 1 = 1 + 1
1 = 2
0 = 1
1927 unique view(s)
no
im probably a little late but at the part where a(b-a)=(b+a)(b-a)
since b=a
b-a=0 and if u multiply 0 each side you would end up with 0
your dividing by zero. you cant divide both sides by (b-a). dividing by zero is undefined
a(b - a) = (b + a)(b - a)
-(b - a) -(b - a)
a = (b + a)
Its not equal
However
"0 IS 1 number" on the number scale.
In the begining is- 0 we now have 1 number. Oh its now 2. or is it three? Now im counting 4! ah <><>
Its called Axiom of infinity i think?
Its like the liers paradox.
A war between what it is and what it means
nice